Supply Lists

Here is the link to the supply lists for my 9th grade homeroom and all math classes. 
http://www.sacredheartcardinals.org/temp.html

Here is a link to a new graphing calculator that has a ton of new features that we will be using in all the math classes this year.  If you have not purchased a graphing calculator this is a great one to consider.  Here is a link about the calculator and the price.  You can buy this calculator for about $100 which is a great cost.  It is called the Casio fx-CG10 PRIZM. http://www.eaieducation.com/Product/533700/Casio%C2%AE_PRIZM_FX-CG10.aspx

TIMES Activity

How many people must be in room before the probability that someone shares a birthday, ignoring the year and ignoring the leap years, becomes at least 50%? 
This problem is known as the Birthday Paradox.
By Hand it's easier to compute the probability that there are no common birthdays.  
1. Start by considering two students. There are 365 days the first student's birthday could land on and 364 days the second student's birthday could land on and not match the first student.
2. So the probability of no common birthday for 2 students is (365 x 364) / (365 x 365) = 0.99726. You could continue this process by adding students until you arrived at about a 50% chance of no common birthday which subtracted from one would mean there would be a 50% of having a common birthday.  This could be a tedious process so...
3. There are two ways to work this problem on the calculator....TABLE function and RECURSION function. 
4. Now lets check this paradox on a few Major League Baseball rosters.  Did you find any matches?
http://mlb.mlb.com/team/roster_40man.jsp?c_id=atl
http://texas.rangers.mlb.com/team/roster_40man.jsp?c_id=tex
http://newyork.yankees.mlb.com/team/roster_40man.jsp?c_id=nyy
5. These are the 40-man rosters so what is the probability that there will be two people with the same birthday?